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Challenge: The Quest for Earth's Twin
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| neutronium76 | Date: Saturday, 26.11.2011, 10:34 | Message # 1 |
 World Builder
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Greece
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| Once Talisman's Challenge finishes I am starting a new challenge: To find the closest matching terra to our home planet!
All planetary parameters will be considered and taken into account. Planet class, planet size (diameter), Mass, Gravity, Distance to parent star, Class of parent star, Orbital period, Rotaion period, inclination to the ecliptic/axial tilt (i.e seasons) And most imp[ortantly: Atmospheric conditions: Pressure, Temperature and greenhouse effect. Theses 3 will have the highest importance i.e. they will be multiplied with a factor of 2 or 3 (open to suggestions). Also gravity will have a high importance factor as well.
Certain criteria will be set for the quest (not yet determined - I am open to suggestions  ):
1. Distance from our solar system (shall it be a matching factor as well? I think not as it will complicate things a lot  )
2. Shall we search in our galaxy only or shall I include more galaxies?
3. Shall I choose one distant Galaxy like Talisman? And not search in our Galaxy at all?
There will be 10 positions for the final ranking. 1st place will be the closest match i.e the deviation from earth's parameters is closest to zero. 2nd place more deviation, and so on, etc..
The challenge will start when Talisman's challenge finishes.
The winner will have the honor to name that planet with his name/nickname or whatever name he wants B).
What do you people think?
PC1:Core i7 970@3.34GHz, 6 cores/12 threads, 12GB DDR3 RAM@1.34GHz, 2x(SLI) GTX-580 GPUs 3GB VRAM(GDDR5)@1GHz, OS:Win7x64SP1
PC2:Core2Quad X9770@3.2GHz, 2 cores/4 threads 4GB DDR2 RAM@1GHz, GTX-285 GPU 1GB VRAM(DDR3)@1.24GHz, OS:WinVistax64SP2
Edited by neutronium76 - Saturday, 26.11.2011, 11:58 |
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| SpaceEngineer | Date: Saturday, 26.11.2011, 14:50 | Message # 2 |
 Author of Space Engine
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Russian Federation
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| I'd like to add another criteria (but not important) - presence of one selena moon with parameters similar to our Moon: 3400 km diameter, 384000 distance from planet, etc.
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| neutronium76 | Date: Saturday, 26.11.2011, 15:17 | Message # 3 |
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World Builder
Group: Users
Greece
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| Quote (SpaceEngineer) I'd like to add another criteria (but not important) - presence of one selena moon with parameters similar to our Moon: 3400 km diameter, 384000 distance from planet, etc.
Definetly! I've read somewhere, a long time ago, that the presence of the moon, with its specific size, orbital parameters, distance from earth, etc.. contributes in the stabilization of earth's axial tilt and rotation and hence is responsible for the existance of seasons and climate stabilization. Don't know if this is scientifically correct though  .
PC1:Core i7 970@3.34GHz, 6 cores/12 threads, 12GB DDR3 RAM@1.34GHz, 2x(SLI) GTX-580 GPUs 3GB VRAM(GDDR5)@1GHz, OS:Win7x64SP1
PC2:Core2Quad X9770@3.2GHz, 2 cores/4 threads 4GB DDR2 RAM@1GHz, GTX-285 GPU 1GB VRAM(DDR3)@1.24GHz, OS:WinVistax64SP2
Edited by neutronium76 - Saturday, 26.11.2011, 15:18 |
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| SpaceEngineer | Date: Saturday, 26.11.2011, 21:47 | Message # 4 |
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Author of Space Engine
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Russian Federation
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| And finally: should this terra have a life?
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| neutronium76 | Date: Saturday, 26.11.2011, 22:32 | Message # 5 |
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World Builder
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Greece
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| Quote (SpaceEngineer) And finally: should this terra have a life?
I have though about this - can't really decide.
Not necessarily IMHO... It may sound weird but there is no 100% guarantee that if a terra has almost identical to earth conditions, will definitely have life. Most likely - yes. Definetly - No  .
PC1:Core i7 970@3.34GHz, 6 cores/12 threads, 12GB DDR3 RAM@1.34GHz, 2x(SLI) GTX-580 GPUs 3GB VRAM(GDDR5)@1GHz, OS:Win7x64SP1
PC2:Core2Quad X9770@3.2GHz, 2 cores/4 threads 4GB DDR2 RAM@1GHz, GTX-285 GPU 1GB VRAM(DDR3)@1.24GHz, OS:WinVistax64SP2
Edited by neutronium76 - Saturday, 26.11.2011, 22:34 |
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| Talisman | Date: Saturday, 26.11.2011, 23:31 | Message # 6 |
 Pioneer
Group: Users
United States
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| This is a great challenge idea!
You don't have to wait for mine to finish
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| SpaceEngineer | Date: Sunday, 27.11.2011, 00:40 | Message # 7 |
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Author of Space Engine
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Russian Federation
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| Quote (neutronium76) Most likely - yes. Definetly - No
With probability 30% - yes 
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| neutronium76 | Date: Sunday, 27.11.2011, 08:23 | Message # 8 |
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World Builder
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Greece
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| Ok. The search criteria will be:
1. The planet must be in our galaxy only. i.e the system must start with 8404 code. Can be in a cluster/nebula as long as the cluster/nebula is in our galaxy  .
2. It doesn't count towards more matching points if the planet's system is closer to our sol i.e. it can be in the oposite side or the edge of milky way.
3. The presence of life is compulsory.
I will try to find a mathematical formula in order to calculate the matching points - help from Space Engineer and/or anybody will be greatly appreciated .
As a reference, the earth's matching score will be:
Code
planet diameter planet's mass pl's orbital period pl's rotation prd
Earth's MS: ---------------------- +/ x (please advice) ------------------- +/ x ----------------------- +/ x ---------------------- +/x
earth's diameter earth's mass erth's orb.period erth's rottn prd
pl's axial tilt pl's age pl's Gravity pl's atm ps pl's temp pl's grhs eff
---------------- +/ x --------------- +/ x ---------------- (x 2) +/x ---------------(x2) +/x ------------(x2) +/x -----------------(x2) +/x
erh's axial tlt erth's age erth's G earth's atm ps earth's Tmp earth's ghs eff
pl's moons +/x moon's size +/x distance from parent
------------------------------------------------------------------- = earth's ideal matching score 15 if adding / 16 if multiplying)
earth's moon +/x moon's sz +/x distance from earth
 :angry2: can't allign the fractions within the code frame  >(
PS: I did not include in the formula the planet's parent star astronomical parameters (Class, spectral type, diameter, mass, temperature, luminosity, distance from planet etc..). Shall I include them? It's going to be really really tough
PC1:Core i7 970@3.34GHz, 6 cores/12 threads, 12GB DDR3 RAM@1.34GHz, 2x(SLI) GTX-580 GPUs 3GB VRAM(GDDR5)@1GHz, OS:Win7x64SP1
PC2:Core2Quad X9770@3.2GHz, 2 cores/4 threads 4GB DDR2 RAM@1GHz, GTX-285 GPU 1GB VRAM(DDR3)@1.24GHz, OS:WinVistax64SP2
Edited by neutronium76 - Sunday, 27.11.2011, 09:30 |
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| Talisman | Date: Wednesday, 30.11.2011, 07:31 | Message # 10 |
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Pioneer
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United States
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| I found a pretty nice one with a single selena moon. Sadly it was not even close to the milky way so I can't submit it.
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| neutronium76 | Date: Wednesday, 30.11.2011, 20:02 | Message # 11 |
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World Builder
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Greece
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| Quote (SpaceEngineer) neutronium76, if you are familiar with LaTeX, you can use this online editor and attach gif image to your message
I'll check it out for next time - thanks Space Engineer!
Quote (SpaceEngineer) Surface gravity is unnecessary as long as it defined by mass and diameter of the planet
Hmm does this mean it is directly proportionsl to the density of the planet? The only reason I consider gravity important is because too much deviation from 1g is not going to help with the evolution of life - at least as we know it here on earth . The closer the planet's "g" to earth "g", the more comfortable the conditions for human colonization. If the above equation you suggest takes gravity into account - even indirectly by measuring of F(D) and F(M) - then it's perfectly fine by me. 
Quote (SpaceEngineer)
This function gives normal distribution with maximum value of 1 then parameter D is equal to Earth's one. So the similarity coefficient k will be between 0 and 1 (or 0% to 100% if you multiply it by 100%).
So the similarity coefficient K should be as close to one as possible, in order for the planet to be as close to earth as possible? Or is it the oposite? i.e close to zero? I am confused . Sorry my brain is a bit rusty with logs and e's ...
PC1:Core i7 970@3.34GHz, 6 cores/12 threads, 12GB DDR3 RAM@1.34GHz, 2x(SLI) GTX-580 GPUs 3GB VRAM(GDDR5)@1GHz, OS:Win7x64SP1
PC2:Core2Quad X9770@3.2GHz, 2 cores/4 threads 4GB DDR2 RAM@1GHz, GTX-285 GPU 1GB VRAM(DDR3)@1.24GHz, OS:WinVistax64SP2
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| SpaceEngineer | Date: Wednesday, 30.11.2011, 22:47 | Message # 12 |
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Author of Space Engine
Group: Administrators
Russian Federation
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| Quote (neutronium76) Hmm does this mean it is directly proportionsl to the density of the planet? The only reason I consider gravity important is because too much deviation from 1g is not going to help with the evolution of life - at least as we know it here on earth . The closer the planet's "g" to earth "g", the more comfortable the conditions for human colonization. If the above equation you suggest takes gravity into account - even indirectly by measuring of F(D) and F(M) - then it's perfectly fine by me.
Where G is a gravitational constant. If M (mass) and R (radius) of a planet is equal to Earth's, than surface gravity is equal automatically.
Quote (neutronium76) So the similarity coefficient K should be as close to one as possible, in order for the planet to be as close to earth as possible? Or is it the oposite? i.e close to zero? I am confused . Sorry my brain is a bit rusty with logs and e's ...
Yes, for pretty Earth's twin the formula gives 1.0 result.
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| neutronium76 | Date: Thursday, 01.12.2011, 07:16 | Message # 13 |
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World Builder
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Greece
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| Aha. Crystal clear now - thanks Space Engineer!
Let the hunting begin then ...
Please all submissions to include exact details of your findings i.e either a screenshot with HUD on (Ctrl+F11), or in written with coordinates in order to check your finding. Remember that screenshot quality - no matter how beatiful it may look - does not count towards matching points. This is NOT a beauty contest - it is a search for a new home.
PC1:Core i7 970@3.34GHz, 6 cores/12 threads, 12GB DDR3 RAM@1.34GHz, 2x(SLI) GTX-580 GPUs 3GB VRAM(GDDR5)@1GHz, OS:Win7x64SP1
PC2:Core2Quad X9770@3.2GHz, 2 cores/4 threads 4GB DDR2 RAM@1GHz, GTX-285 GPU 1GB VRAM(DDR3)@1.24GHz, OS:WinVistax64SP2
Edited by neutronium76 - Thursday, 01.12.2011, 07:17 |
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| SimonDoo | Date: Thursday, 01.12.2011, 09:00 | Message # 14 |
 Observer
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France
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| Great challenge indeed !
The one I post in the "best terra challenge" is off contest, as it's not in the Milky Way, but as an example, it has a nice similarity coeff K=38%
Its main dissimilarities : more than twice earth mass, 5 years orbit period, and a short 10 hours day only.
The same with a 1 year orbit would reach K=67%
Asus G74SX - Core i7 - 2670QM, 2.2Ghz - 8GB Ram
Nvidia GeForce GTX 560M - 3GB - v285.74
Win 7 Home Premium 64-bit - DirectX11
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| SpaceEngineer | Date: Thursday, 01.12.2011, 18:38 | Message # 15 |
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Author of Space Engine
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Russian Federation
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| If someone make an Excel document for compute k, please post it here.
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